How do you figure out the equation for a line, when only given one point of (2,5)?
you can't
you wil get infinitely many lines passing through that point.
since there are infinitely many like dh said
I have a graph of the line, but can't put it up here, unfortunately...
do you know where it crosses the y axis?
take a picture and attach it using the attach file button | | v
or any other point on the line?
No...it only crosses the y axis....and it does not cross it in a specific spot, like the meeting spot of 4 boxes or anything...
you use the point-slope formula and then change it to slope-intercept form
How can I use the point-slope formula, with only one point?
oh wait. you need another point to find out the slope. sorry nvm u cant.
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