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substitution: the integral of cos3xdx, u=3x
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cosu du/3
\[du=3 d\[\frac{1}{3}\int\limits_{}^{}\cos(u) du=\frac{1}{3}\sin(u)+C\]x\]
-sinu/3+c
not negative derivative of sinu is cosu
u = 3x, du = 3dx \[\int(cos(3x)dx=\frac{1}{3}\int cos(u)u =\frac{1}{3}sin(u)=\frac{1}{3}sin(3x)\]
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ohh sorry
=1/3*sin(3x)+C
oh yeah! +C
satellite your answer was so far off without that C
lol
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ok so who's right?
obviously me
remember, i'm the one that doesn't know what's going on :]
oh, right obviouslyyy. silly me.
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