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Mathematics 17 Online
OpenStudy (anonymous):

Square the polynomial 5a - 2c - 3e

OpenStudy (anonymous):

Do you mean: (5a-2c-3e)^2

OpenStudy (anonymous):

\[(5a - 2c - 3e)^2\]

OpenStudy (anonymous):

The we do: (5a-2c-3e)(5a-2c-3e)= 5a^2-20ac-30ae+4c^2+12ec+9e^2

OpenStudy (anonymous):

Thks Can you help me with another one then :D

OpenStudy (anonymous):

We get that answer after expanding and combing like terms, if you want i can write out the whole process

OpenStudy (anonymous):

sure, hit me with it

OpenStudy (anonymous):

\[(2x + 3y - 5z)^2\]

OpenStudy (anonymous):

Okay this is really: \[(2x+3y-5z)(2x-3y-5z)\]

OpenStudy (anonymous):

I mean \[(2x+3y-5z)(2x+3y-5z)\]

OpenStudy (anonymous):

After multiplying each term we get: \[2x^2+12yz-20xz+9y^2-30yz+25x^2\]

OpenStudy (anonymous):

\[4x^2 + 9y^2 + 25z^2 + 12xy - 20 xz - 30yz\]

OpenStudy (anonymous):

yeah your right the 2x^2 is suppose to be 4x^2, my mistake

OpenStudy (anonymous):

How do you get -20xz?

OpenStudy (anonymous):

That results from multiplying 2x and -5x and then combing the terms, since the product -10xz appears twice, we get -20xz

OpenStudy (anonymous):

Finally I get it I was looking at the wrong problem when I was trying to multiply

OpenStudy (anonymous):

Thks

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