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OpenStudy (anonymous):
Square the polynomial
5a - 2c - 3e
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OpenStudy (anonymous):
Do you mean: (5a-2c-3e)^2
OpenStudy (anonymous):
\[(5a - 2c - 3e)^2\]
OpenStudy (anonymous):
The we do: (5a-2c-3e)(5a-2c-3e)=
5a^2-20ac-30ae+4c^2+12ec+9e^2
OpenStudy (anonymous):
Thks
Can you help me with another one then :D
OpenStudy (anonymous):
We get that answer after expanding and combing like terms, if you want i can write out the whole process
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OpenStudy (anonymous):
sure, hit me with it
OpenStudy (anonymous):
\[(2x + 3y - 5z)^2\]
OpenStudy (anonymous):
Okay this is really: \[(2x+3y-5z)(2x-3y-5z)\]
OpenStudy (anonymous):
I mean \[(2x+3y-5z)(2x+3y-5z)\]
OpenStudy (anonymous):
After multiplying each term we get: \[2x^2+12yz-20xz+9y^2-30yz+25x^2\]
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OpenStudy (anonymous):
\[4x^2 + 9y^2 + 25z^2 + 12xy - 20 xz - 30yz\]
OpenStudy (anonymous):
yeah your right the 2x^2 is suppose to be 4x^2, my mistake
OpenStudy (anonymous):
How do you get -20xz?
OpenStudy (anonymous):
That results from multiplying 2x and -5x and then combing the terms, since the product -10xz appears twice, we get -20xz
OpenStudy (anonymous):
Finally I get it I was looking at the wrong problem when I was trying to multiply
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OpenStudy (anonymous):
Thks
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