9x^2+9x^3-7-13x/3x+4

Question

anonymous · Answer

3x+4)9x^3+9x^2-13x-7(3x^2-x-1/3
          9x^3+12x^2
-----------------------
                   -3x^2-13x-7
                   -3x^2-12x
---------------------
                           -x-7
                           -x-4/3
-------------------------
                              -17/3

anonymous · Answer

here 3x^2-x-1/3 is the quotient and -17/3 is remainder

anonymous · Answer

$$(3x ^{2}-3x-1/3) -17/(9x+12) $$

anonymous · Answer

$$\frac{9x^2+9x^3-7-13x}{3x+4}=\frac{-9x^3+10x-7}{4}$$

anonymous · Answer

how Craigwillium?

anonymous · Answer

can u please show the steps...

anonymous · Answer

It's a matter of simplification by moving around exponents.  I only did the simplification part.

anonymous · Answer

@craig Oh even i em interested in seeing the proof