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what is the vertex of y^2=4ax-1
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hello amstre. you missed the small latex tutorial
i seen parts of it i think :)
power was out for a few hours over here ....
what is the vertex of y^2=4ax-1
is that 4a(x-1) ? or just a straight run thru?
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it is 4ax-1
then you factor out the 4a and get: \[y^2=4a(x-\frac{1}{4a})\]
and the vertex is at: (1/4a , 0)
otherwise you have a typo; and you really meant to say: 4a(x-1) in which case its (1,0)
vertex without a.I want only the numerical value
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you cant have it both ways; either you typed it correctly and we leave it in; or you mistyped and we take it out
ok Thanks a lot
youre welcome :)
it is \[(\frac{1}{4a},0)\] yes?
yes absolutely.
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it would be if we get an accurate portrayal of the equation ;)
whew
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