Question

sin Ø=
cos Ø =
tan Ø =

Answer 1

\[\sin Ø= s/ \sqrt{s ^{2}+t ^{2}}\ \
cos Ø = t/ \sqrt{s ^{2}+t ^{2}} \
tan Ø = s/t\]

Answer 2

why s sq same for t

Answer 3

well as you know sin Ø = opposite/hypotenuse
cos Ø = adjacent/hypotenuse and
tan Ø = adjacent/opposite

opposite = s
adjacent = t
and hypotenuse = sqrt(s^2+t^2) by pythag

Answer 4

oh ok thank you