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x^4-9x^2<0 (Solve for x)
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from -3 to 3 except at x = 0
from -3 to 3.. x=0
\[x^2(x^2-9)=x^2(x-3)(x+3)\]
zeros at -3, 0, and 3
since the term \[x^2\] gives a zero, and it is squared (fancy term is the multiplicity of the 0 is 2) it does not change sign there.
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so this thing is positive, then negative, then positive. positive to the left of -3, then negative until 3, then positive after.
if you want a fancy answer write \[(-3,0)\cup (0,3)\]
thanks man. i like that graphing site.
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