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The Fibonacci sequence can be defined recursively as SEE EQUATION IN COMMENTS. What is the 10th term?
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\[a _{1} = 1\] \[a _{2} = 1\] \[a _{n} = a _{n-1} + a _{n - 2} forn \ge 3\]
depends on the starting terms
1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,...
1,1,2,3,5,8,13,21,34,55,...
THE fibber starts at 1 and 1 tho right?
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what rubin said
10th term is 55
ta ta nee chi near tens guns lazarus rosemines mishunbabies mishunbabiess is ow i recall the first 10 factorial lol
if you want the nth term and have a calculator y ou can compute \[\frac{1}{\sqrt{5}}(\frac{1+\sqrt{5}}{2})^n-\frac{1}{\sqrt{5}}(\frac{1-\sqrt{5}}{2})^n\]
1,1,2,6,24,120,720,5040,40320,362880,3628800
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