Question

I am working with congruent quadrilaterals and I do not understand it. I need to figure a\out the value of x and y
4x 28
___= ___
28 8y+2

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

For something to be explicitly equal 4x=28 and 28=8y+2. At least, thats how it works in linear algebra. Without that fact, you can't solve 2 unknowns with one equation.

Answer 3

Amistre, am I right?

Answer 4

yes you are

Answer 5

as far as i can tell ;)

Answer 6

it can be solved; but it creates a line

Answer 7

I figure this solves out like partial fraction decomp. Linear algebra ftw? haha

Answer 8

I made a mistake
the number above the 8y+2 should be 34 not 28

Answer 9

All that does is change my first equation to 4x=34

Answer 10

cross multiply; or try a 0y in the top

Answer 11

4x(8y+2) = 34 (28)

Answer 12

ok

Answer 13

32xy +8 = 952

32xy = 952 - 8

xy = 944/32 = 29.5

Answer 14

now if you know x or y; you can determine the missing peice

Answer 15

im not sure if solving for y and subing it in is a good idea or not

Answer 16

looks to be the same regardles

Answer 17

I am so confused

Answer 18

cant read your mind; try to tell us why?

Answer 19

did you type in in right?

Answer 20

perhaps x = 34/4

and y = 26/8

Answer 21

Thank you

Answer 22

itd be better if we could see the problem :) but you are welcome

Answer 23

It gives me two shapes both look similiar. across the top of one is 4x and along the side it is 34. The next shape across the top is 28 and along the side is 8y+2. They are congruent and I am supposed to find the value of x and y.

Answer 24

4x = 28
x = 28/4
x = 7

34 = 8y+2
32 = 8y
y = 32/8 = 4

Answer 25

equate sides and solve for the variable

Answer 26

Thank you