Question

differenitate
g(t)=9t^3 sin t
I got 9t^2(3sint-tcost) to be my answer

Answer 1

product rule:

Answer 2

27t^2sin(t) + 9t^3cos(t)

Answer 3

yes i did use the product whats the answr

Answer 4

that is the answer; you subtracted instead of added

Answer 5

vdu+udv

Answer 6

You should use the "Equation" button to formulate your question. Your original equation could be interpreted as:

\[g(t) = 9t^{3\sin(t)}\]
or
\[g(t) = 9t^{3}\sin(t)\]

Answer 7

i always get mess up on the sign!!! ughhh lol

Answer 8

the second one GarettM

Answer 9

Yea I realize, I'm just saying

Answer 10

ok i will do that next time

Answer 11

You should press the GOOD ANSWER button when someone answers your question, btw.