Question

Write the equation of the hyperbola whose vertices are at (0,±4) and whose foci are at (0,±11)

Answer 1

the y axis is the parallel; and in hyper that gets the lower number

Answer 2

the trick is finding the missing 'b^2'

Answer 3

the center is the origin;

Answer 4

y^2 x^2
--- - ---- = 1
16 b^2

Answer 5

5.5^2 - 4^2 = b^2; if I recall it correctly

Answer 6

14.25 = b^2 then; but we can prolly work it up better

Answer 7

57/4 hmmm

Answer 8

So that is the equation of the hyperbola?

Answer 9

no.... still trying to get it in my head right; i halved the 4 and 11 and wasnt sposed to

Answer 10

b^2 = 105 ..... 11^2 = b^2 + 4^2

11^2 - 4^2 = b^2 = 105

Answer 11

y^2 x^2
---- - ---- = 1 ; is my best shot at it
16 105

Answer 12

Okay, thanks!