Question

solve (x+5)/(x^2-x-12)less than or equal to 0

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

i need to find x values

Answer 3

thanks!

Answer 4

\[x^2-2x-17\ge0\]

Answer 5

use quadratic formula to find x

Answer 6

wrong

Answer 7

\[frac{x+\5\}\{\(x-\4\)\(x+\3\)\}\<\=\0\]

Answer 8

unknown in denominator

Answer 9

multiply by the square of the denominator, also it factors

Answer 10

No your wrong the question says that it is greater than 0 not 1. Neither can you transpose such terms in an inequality.
(x+5)/(x^2-x-12)<0
(x+5)/((x-4)(x-3))<0
so the solutions are x is from (\[\infty\],-5) and (3,4)

Answer 11

(x-5)(x-4)(x+3) <=0

Answer 12

oh sorry the infinity is with a minus sign

Answer 13

oh i missed the zero on right
elec is right

Answer 14

4<=x<=5 x<=-3

Answer 15

but

Answer 16

x+5/(x-4)(x+3) less than or equal to zero

Answer 17

must exclude the zero of the denomiantor

Answer 18

fraction is negative when one of num or den is neagtive

Answer 19

so the answer is 4<x<=5 and x<-3

Answer 20

^FINAL ANSWER

Answer 21

x=5 we have zero
x=4 and x=-3 the fraction is undefined
test areas before and after each number we found {-3,4,5}
you want to see if you get negative for any of these intervals
and don't foget to include 5 in your answer since we also want the fraction to be zero

Answer 22

oops that is suppose to be -5

Answer 23

lols, so many people writting stuff, confusing me :|

Answer 24

x<=-5 and -3<x<4 , FINAL ANSWER lols

Answer 25

Just use wavy curve after factorizing the answer you get x<-5 and 3<x<4

Answer 26

i know i am a bit confused as well but thank you all for your help :)!

Answer 27

so if we plug in a number before -5 like -6
we get (-6+5)/(-6-4)(-6+3)=-/-*-=-
so the interval (-inf,-5] is part of our answer
not lets check the other intervals
lets look between -5 and -3
plug in a number in btw like -4
(-4+5)/(-4-4)(-4+3)=+/-*-=+
so this interval is not part of our anwswe
now lets look at -3 to 4
plug in a number btw these two numbers like 0
(0+5)/(0-4)(0+3)=+/-*+=-
so this (-3,4) is apart of our answer
now finally the last interval 4 to infinity
plug in random number btw these two like 6
(6+5)/(6-4)(6+4)=+/+*+=+
so not apart of our answer
final answer is (-inf,-5]U(-3,4)

Answer 28

what elelcengineer got gj

Answer 29

^ I personally dont like the sub in points method, not very reliable

Answer 30

should draw a graph

Answer 31

how do you draw a graph without calculus?

Answer 32

i guess you could use algebra takes longer

Answer 33

there are very simple rules

Answer 34

all you need are the intercepts and the "order" of the roots

Answer 35

why don't you think the sub in points thing is reliable?

Answer 36

if its order 1, it goes straight though , if its an even order then it is tangent and bounches back up

Answer 37

you don't need to know if a function is increaing and decreasing?

Answer 38

if its odd order then its an inflexion point on the intercept

Answer 39

then you look at the sign of the high power of x to see it the graph "approaches from the 1st quadraqnt or the 2nd quadrant

Answer 40

really rough picture of the graph in question

Answer 41

all you need to know are when its above and when its below, doesnt need to be very accurate

Answer 42

say I had something like y= (3-x)( x+5)^3 (x-1)^4

Answer 43

its graph would look something like that^

Answer 44

i cant look at your graphs :(

Answer 45

because the sign of the highest power of x is negative, thsat means at large x the expression is negative , why it approaches from below

Answer 46

Here is a word problem i am having trouble with: A train leaves a station heading east at 8 am traveling at a rate of 60 mph. At 9:30 am a 2nd train leaves the same station on a parallel track also heading east traveling at a rate of 900 mph. At what time will the 2nd train catch up to the 1st train?

Answer 47

900 mph?? - should'n't that be 90?

Answer 48

yes sorry that was my mistake it is 90mph