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Mathematics 14 Online
OpenStudy (anonymous):

3-8/x divided by x+4/5x

OpenStudy (anonymous):

-25x/ x^2+4x

OpenStudy (anonymous):

Do you want a more detailed explanation?

OpenStudy (anonymous):

that answer is not correct

OpenStudy (anonymous):

have to find the lcd

OpenStudy (anonymous):

yes find the lcd

OpenStudy (anonymous):

oh wait

OpenStudy (anonymous):

this is a divison problem, so to turn this problem into a multiplication problem we multiply 3-8/x by the reiprocal or x+4/5x

OpenStudy (anonymous):

here is another one 3-5/x divided by x+2/5x

OpenStudy (anonymous):

so in reality the problem will be \[3-8/x *5x/x+4\]

OpenStudy (anonymous):

okay for the newest problem you posted, we multiply 3-5/x by the reciprocal of x+2/5x, or 5x/x+2

OpenStudy (anonymous):

so the problem will look like this: 3-5/x times 5x/x+2

OpenStudy (anonymous):

u have to find the lcd though

OpenStudy (anonymous):

wait is the the problem: (3)-(5/x)/(x)+(2/5x)

OpenStudy (anonymous):

or is the 3-5 the numerator

OpenStudy (anonymous):

yes thats the problem

OpenStudy (anonymous):

oh then we do first have to find the lcd.

OpenStudy (anonymous):

which is 5x

OpenStudy (anonymous):

well, for 3-5/x the lcd is x

OpenStudy (anonymous):

and for x+2/5x the lcd is 5x

OpenStudy (anonymous):

i believe u have to find a common lcd

OpenStudy (anonymous):

5x would work for both x and 5x

OpenStudy (anonymous):

are these two seperate problems?

OpenStudy (anonymous):

b/c 5x will work for one but not for the other

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