Mathematics
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OpenStudy (anonymous):
3-8/x divided by x+4/5x
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OpenStudy (anonymous):
-25x/ x^2+4x
OpenStudy (anonymous):
Do you want a more detailed explanation?
OpenStudy (anonymous):
that answer is not correct
OpenStudy (anonymous):
have to find the lcd
OpenStudy (anonymous):
yes find the lcd
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OpenStudy (anonymous):
oh wait
OpenStudy (anonymous):
this is a divison problem, so to turn this problem into a multiplication problem we multiply 3-8/x by the reiprocal or x+4/5x
OpenStudy (anonymous):
here is another one 3-5/x divided by x+2/5x
OpenStudy (anonymous):
so in reality the problem will be \[3-8/x *5x/x+4\]
OpenStudy (anonymous):
okay for the newest problem you posted, we multiply 3-5/x by the reciprocal of x+2/5x, or 5x/x+2
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OpenStudy (anonymous):
so the problem will look like this: 3-5/x times 5x/x+2
OpenStudy (anonymous):
u have to find the lcd though
OpenStudy (anonymous):
wait is the the problem: (3)-(5/x)/(x)+(2/5x)
OpenStudy (anonymous):
or is the 3-5 the numerator
OpenStudy (anonymous):
yes thats the problem
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OpenStudy (anonymous):
oh then we do first have to find the lcd.
OpenStudy (anonymous):
which is 5x
OpenStudy (anonymous):
well, for 3-5/x the lcd is x
OpenStudy (anonymous):
and for x+2/5x the lcd is 5x
OpenStudy (anonymous):
i believe u have to find a common lcd
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OpenStudy (anonymous):
5x would work for both x and 5x
OpenStudy (anonymous):
are these two seperate problems?
OpenStudy (anonymous):
b/c 5x will work for one but not for the other