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Mathematics 17 Online
OpenStudy (anonymous):

divide and simplify v^8/v^11

OpenStudy (anonymous):

y^-3

OpenStudy (anonymous):

aka 1/y^3

OpenStudy (anonymous):

ok so it would actually be a positive 3?

OpenStudy (anonymous):

v^3 ?

OpenStudy (anonymous):

no... 1 over y^3

OpenStudy (anonymous):

oh ok 1/v^3

OpenStudy (anonymous):

these are easy, just subtract the top exponent from the bottom

OpenStudy (anonymous):

I mean bottom from the top, sorry

OpenStudy (anonymous):

ok so it would be v^-3 but the when it was simplified be 1/v^3

OpenStudy (anonymous):

\[It's\ v^ -3\]

OpenStudy (anonymous):

oh ya v haha

OpenStudy (anonymous):

but depending on how you simplify it, 1/v^3 is the same as v^-3

OpenStudy (anonymous):

\[x\ power\ anything\ is \ 1divided \ by\ anything\]

OpenStudy (anonymous):

but the question does not ask you to write it using only positive exponents it simply says ivide and simplify

OpenStudy (anonymous):

Simplifying it could go either way, usually people like positive exponents...

OpenStudy (anonymous):

\[both\ are\ same\ by\ the\ way\ just\ don't\ worry\]

OpenStudy (anonymous):

usually a teacher will accept either one

OpenStudy (anonymous):

ok great thanks yall

OpenStudy (anonymous):

\[welcome\]

OpenStudy (anonymous):

\[\sqrt[5]{-1/1024?}\]

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