Mathematics
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OpenStudy (anonymous):
divide and simplify v^8/v^11
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OpenStudy (anonymous):
y^-3
OpenStudy (anonymous):
aka 1/y^3
OpenStudy (anonymous):
ok so it would actually be a positive 3?
OpenStudy (anonymous):
v^3 ?
OpenStudy (anonymous):
no... 1 over y^3
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OpenStudy (anonymous):
oh ok 1/v^3
OpenStudy (anonymous):
these are easy, just subtract the top exponent from the bottom
OpenStudy (anonymous):
I mean bottom from the top, sorry
OpenStudy (anonymous):
ok so it would be v^-3 but the when it was simplified be 1/v^3
OpenStudy (anonymous):
\[It's\ v^ -3\]
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OpenStudy (anonymous):
oh ya v haha
OpenStudy (anonymous):
but depending on how you simplify it, 1/v^3 is the same as v^-3
OpenStudy (anonymous):
\[x\ power\ anything\ is \ 1divided \ by\ anything\]
OpenStudy (anonymous):
but the question does not ask you to write it using only positive exponents it simply says ivide and simplify
OpenStudy (anonymous):
Simplifying it could go either way, usually people like positive exponents...
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OpenStudy (anonymous):
\[both\ are\ same\ by\ the\ way\ just\ don't\ worry\]
OpenStudy (anonymous):
usually a teacher will accept either one
OpenStudy (anonymous):
ok great thanks yall
OpenStudy (anonymous):
\[welcome\]
OpenStudy (anonymous):
\[\sqrt[5]{-1/1024?}\]