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can u help me with this one sqrt(x+2)=sqrt(x)+1
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square both sides
i could have sworn mininaya write a very nice answer to this one. square both sides
so then x+2 = x +2sqrt(x)+1 no?
\[\sqrt{x+2}=\sqrt{x}-1\] \[x+2=(\sqrt{x}+1)^2=\sqrt{x}\sqrt{x} + 2\sqrt{x}+1=x+2\sqrt{x}+1\]\]
so sqrt(x) = 1/2?
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x = 1/4
so subtracting x from both sides gives \[2=2\sqrt{x}+1\] subtract 1 gives \[1=2\sqrt{x}\] divide by 2 to get \[\frac{1}{2}=\sqrt{x}\] square again to get \[\frac{1}{4}=x\]
what light said
ok thanks
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