Question

can anyone help me solve systems of equations with 3 varibles... the first equation is 2x + 2y +3z=14 second equation is 3x + y - z=-3 third equation x + y +2z =9 any help greatly appreciated

Answer 1

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Answer 2

Can be done using Cramers rule or the determinant method

Answer 3

x + y +2z = 9 [*-2] x + y +2z = 9 [*-3]
2x +2y +3z =14 3x + y - z = -3



-2x -2y -4z = -18 -3x -3y -6z = -27
2x +2y +3z = 14 3x + y - z = -3
----------------- ------------------
-z = -4 -2y -7z = -30
z = 4

-2y -7(4) = -30
-2y -28 = -30
-2y = -2

y=1

Answer 4

x + y +2z = 9

x + 1 +2(4) = 9

x = 0 dbl chk

Answer 5

i think it checks .... but i tend to be biased :)