Can somebody explain WHY there is not a solution to the below system?
3x = 2y -4
6x -4y = -4
my answer key to this system says, 'no solution.' I did have problems trying to find a solution..but I would like a specific explanation as to why there is no solution to this system...
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OpenStudy (anonymous):
it does have a solution
OpenStudy (anonymous):
the program you are using is wrong
OpenStudy (anonymous):
I'm in an Intermediate Algebra College course...you saying there's a typo in my textbook?
OpenStudy (anonymous):
The problem specifically asked me to use the substitution method to find the solution...
OpenStudy (anonymous):
lol you are right, wasnt thinking too hard
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OpenStudy (anonymous):
rearranage first for x'
x= (2y-4)/ 3
OpenStudy (anonymous):
sub into second
2(2y-4) -4y =-4
OpenStudy (anonymous):
gives -8 = -4
OpenStudy (anonymous):
false statement, so no solution
OpenStudy (anonymous):
Wait...what about the /3? Don't you somehow substitute that in with the 2y-4, in the second equation?
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OpenStudy (anonymous):
2(3x-2y+4)-(6x-4y+4)
hence both x and y terms cancels..so no solution