Question

Compute (f o g )(x), given the functions below:
f(x) = (3x-4)/(4x-5)
g(x) = 1/4x

Answer 1

fog=(3*1/4x -4)*(4*1/4x -5)
so u put g(x) instead of x in the F(x)

Answer 2

did that; want to see how far is can factorize

Answer 3

f(g(x))=\[(3/4x-4)/(4/4x-5)=(3-16x)/(4-20x)\]

Answer 4

that isnt correct

Answer 5

pull out a 4 in the denom

Answer 6

thanks

Answer 7

Is X in the denominator?

Answer 8

yes

Answer 9

brackett that cannot be right

Answer 10

(3-16x)/4x (3-16x) 4x 3-16x
------------=---------*-----------=----------
(4-20x)/4x 4x 4-20x 4-20x
Brackett is right

Answer 11

@akileez: there's x in the denominator of the fraction in both numerator and denomenator of the function, hence it'll get cancelled...hope its not confusing u :)

Answer 12

one sec: redoing - thanks guys

Answer 13

uw :)

Answer 14

but, my answer choices dont reflect what you calc'd

Answer 15

it doesn't?
wht is it?

Answer 16

a) (1/4) (4x-5)/(3x-4)

Answer 17

b) (1/4)(12x^2-12x-5)/(4x-5)x

Answer 18

c) (1/4)(16x-3)/(5x-1)

Answer 19

d) ((4(3x-4)x))/(4x-5)

Answer 20

e) (1/4)(16x+13)/(5x+4)

Answer 21

it is C cause 4-20x=4(1-5x)
and that is the only alternative tht has tht in denom.

Answer 22

both up and down r divided with 4 so....
Wht do u think Brackett?

Answer 23

that makes sense to me; i see where I misplaced the x in the denom before hand - thanks guys very helpful!

Answer 24

^_^