The initial velocity of a projectile is 600m/s. If the longitude of the cannon is 150 cm, what is the acceleration of the projectile when it leaves the cannon? Any idea?

Question

anonymous · Answer

wat d'u mean by longitude?

anonymous · Answer

the length of the cannon is 150cm.

anonymous · Answer

information insufficient. nothing about the inclinatoin of cannon?

anonymous · Answer

No, but I think the position of the cannon must be 45° from the ground. That is not important anyway:

anonymous · Answer

the answer is 1.2*10 ^5 m/s2

anonymous · Answer

that is all i got from my book

anonymous · Answer

acceleration is the derivative of the velocity, but you must have some sort of equation that connects initial velocity with 'longitude" whatever that means, yes?

anonymous · Answer

@satellite73: You finally got a picture :D

anonymous · Answer

Yeah I thiink there must be. But I dont have ti. That is all I got from my book.

anonymous · Answer

just what I wrote above

anonymous · Answer

I think the author stated the exercise in not the correct way

anonymous · Answer

Thanks guys Im gonna leave this exercise in blank

anonymous · Answer

yeah it is the bike amistre got for getting 1000 medals.  i stole it

anonymous · Answer

http://media.wiley.com/product_data/excerpt/12/EHEP0007/EHEP000712.pdf

anonymous · Answer

Is there an specific part I should read? That is long dude