some how we need to expand with out really expanding it because thats to long to do
like we can find the coefficient of x in 5x^2-2x+4
the coefficient of x is -2
so we got to see if there is some kind of trick we can do to finding the coefficient in your expansion
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OpenStudy (saifoo.khan):
no, but there must b a way!
i mean its an O'level ques.
I hav my cambridge ppr tmmrw, & im badly stuckk. :/
myininaya (myininaya):
have you ever seen a problem like this one?
can i find an example somewhere?
OpenStudy (saifoo.khan):
umm, my scanner isnt working now othrwise i should hav scannd & sndd u the example. Its in my book,
myininaya (myininaya):
is it too long to type in latex form?
myininaya (myininaya):
or you don't even have to use latex
im sure i can make it out
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OpenStudy (saifoo.khan):
:/
OpenStudy (saifoo.khan):
thnks for your Help.. =)
myininaya (myininaya):
maybe we can do something with pascals's triangle one sec
OpenStudy (saifoo.khan):
Yeah, its the same thing.
OpenStudy (anonymous):
the coefficient of the x term?
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OpenStudy (saifoo.khan):
Yes.
the ques says:
Find the coefficient of x in the expansion
OpenStudy (anonymous):
if that is all you want it is -320
myininaya (myininaya):
satellite how did you do it so fast
OpenStudy (saifoo.khan):
Wow!
OpenStudy (saifoo.khan):
no, not wow.
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myininaya (myininaya):
is that right khan?
OpenStudy (saifoo.khan):
its somrthing
–960 + 320
= –640
OpenStudy (saifoo.khan):
this is the final answer
OpenStudy (saifoo.khan):
satelite??? HOWW?
myininaya (myininaya):
the way im doing it is too long lol
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OpenStudy (anonymous):
do u want the highest index of the variable????
OpenStudy (anonymous):
ok here goes.
OpenStudy (anonymous):
\[(2-5x)^6 = 2^6 + stuff\]
OpenStudy (anonymous):
if yes then highest index will b 16
OpenStudy (anonymous):
and the x term in
\[(1+x)^{10}=10x\]
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OpenStudy (anonymous):
so one way to get an x is
\[2^6\times 10x=640x\]
OpenStudy (anonymous):
the other way to get an x term is
\[(1+x)^{10}=1+stuff\]
OpenStudy (anonymous):
and the x term in
\[(2-5x)^6\] is
\[6\times (-5x)^2\times 2^5\]
OpenStudy (anonymous):
binomial explansion yes? it is \[6ab^5\] where a = -5x and b = 2
myininaya (myininaya):
(-5x)^1*?
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OpenStudy (anonymous):
i just put that in there to make it match up. the term is
\[6ab^5\]
OpenStudy (anonymous):
so we get \[6\times (-5) \times 2^5=-960\]\]
OpenStudy (anonymous):
combining like terms, as we say in the math biz, gives
\[-960x+640x=-320x\]
OpenStudy (anonymous):
k?
OpenStudy (anonymous):
oops yes myininaya i made a typo. it should be
\[6(-5x)^12^5\] sorry
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OpenStudy (anonymous):
it is the x term so certainly not
\[(-5x)^2\] like i wrote. answer is right tho
myininaya (myininaya):
:)
OpenStudy (anonymous):
good thing they only asked for the x term. imagine what you would have to do if you wanted the x^2 term!
myininaya (myininaya):
i like to here you made a mistake
it makes me feel good
lol
OpenStudy (anonymous):
answer was right, so that only counts as a typo!
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myininaya (myininaya):
no im putting this down in my scorebook verus you
i think i might be winning now
myininaya (myininaya):
gj satellite on the problem
OpenStudy (anonymous):
no! answer right = typo. answer wrong = mistake! thnx
btw you have way more fans than i do
myininaya (myininaya):
you have more medals
i guess they just pretend to like me
OpenStudy (anonymous):
now i think it is beer o'clock.
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