factor -x2+12x+28?
help?
okay the factored form is: -(x-14)(x+2)
we must first factor out the negative, leaving us with (x^2-12x-28)
Then with (x^2-12x-28), we must find two numbers that multiply to be -28 and add up to be -12
In this case -14 and 2 are those numbers
thanks!!!!!!!!!
factors will be (x-14) (-x-2) so x = 14 or x = -2 (and not 2) if u put 2 and calculate u will not get zero but will get it with -2
Fact is, that -(x-14)(x+2) is a factored form of -x2+12x+28
-(2)^2 + 12(2) + 28 = -4 + 24 + 28 = 48 and not zero -(-2)^2 + 12(-2) + 28 = -4 -24 + 28 = 0
Remember the original expression was not an equation. It doesn't equal anything except whatever you assign to x. It did not say it equaled zero.
In this case we are not looking for zero, we are just factoring
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