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OpenStudy (anonymous):
factor -x2+12x+28?
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OpenStudy (anonymous):
help?
OpenStudy (anonymous):
okay the factored form is: -(x-14)(x+2)
OpenStudy (anonymous):
we must first factor out the negative, leaving us with (x^2-12x-28)
OpenStudy (anonymous):
Then with (x^2-12x-28), we must find two numbers that multiply to be -28 and add up to be -12
OpenStudy (anonymous):
In this case -14 and 2 are those numbers
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OpenStudy (anonymous):
thanks!!!!!!!!!
OpenStudy (anonymous):
factors will be (x-14) (-x-2)
so x = 14 or x = -2 (and not 2)
if u put 2 and calculate u will not get zero but will get it with -2
OpenStudy (anonymous):
Fact is, that -(x-14)(x+2) is a factored form of -x2+12x+28
OpenStudy (anonymous):
-(2)^2 + 12(2) + 28 = -4 + 24 + 28 = 48 and not zero
-(-2)^2 + 12(-2) + 28 = -4 -24 + 28 = 0
OpenStudy (radar):
Remember the original expression was not an equation. It doesn't equal anything except whatever you assign to x. It did not say it equaled zero.
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OpenStudy (anonymous):
In this case we are not looking for zero, we are just factoring
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