Find a parametric equation for the osculating circle to the ellipse 7x^2 + 5y^2 = 35 at (-sqrt(5),0).
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osculating?
root7cost, root7sint
t= pi
The osculating circle would be a circle that not only goes through the point (2,0) but has the same slope and curvature as the ellipse at that point.
why 2,0??
sorry its -sqrt(5),0
so isnt it the auxilliary circle?
not it doesnt pass through the point..pellet
x=rcost, y=rsint not plug in (-root5, 0) and then equate the slopes of the ellipse and cicle..gives u 2 eqns in r and t
isnt it?
i guess ... so didn't work it out...laurbear:best thing is to search net for this problem...they wud'ved solved it already so get it done :)
is my method wrong?
i don't know exactly boss...i'm not in mood for solving now... :/
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