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Mathematics 8 Online
OpenStudy (anonymous):

x^2+y^2=2 y+3x=-2

OpenStudy (anonymous):

plz help.. two problems due in 25 min

OpenStudy (anonymous):

non linear equations

OpenStudy (anonymous):

what are you trying to do? solve for y?

OpenStudy (anonymous):

no im trying to solve the systems of equations

OpenStudy (anonymous):

points x,y and there may be more than one

OpenStudy (anonymous):

Ive got this and the exact same type of problem then im done but there due in 20 min and i ahve no clue how to do it

OpenStudy (anonymous):

Hey myninya can you talk on group chat after u answer this thx :)

myininaya (myininaya):

y+3x=-2 implies y=-2-3x the other the equation we have x^2+y^2=2 lets plug that first equation y=-2-3x into the second equation x^2+y^2=2 x^2+(-2-3x)^2=2 x^2+(4+2(-2)(-3x)+9x^2)=2 x^2+4+12x+9x^2=2 10x^2+12x+4-2=0 10x^2+12x+2=0 5x^2+6x+1=0 you can solve for x right?

OpenStudy (anonymous):

okay, they intersect at (-1.7,3.1)

OpenStudy (anonymous):

(17/10,and 31/10) is that right??

myininaya (myininaya):

5x^2+5x+x+1=0 5x(x+1)+(x+1)=0 (5x+1)(x+1)=0 5x=-1 x=-1 x=-1/5 they intersect at two points we can find the corresponding values

myininaya (myininaya):

(-1/5, -2-3(-1/5))=(-1/5,-2+3/5)=(-1/5,-7/5) (-1,-2-3(-1))=(-1,-2+3)=(-1,1)

OpenStudy (anonymous):

I hate to be a pain in the you know what but would you mind helping me with one more before you go, this is a huge help!!!

OpenStudy (anonymous):

x^2+y^2=30 x-y^2=-10

OpenStudy (anonymous):

okay you do exactly the same steps are before but this time y = root(x+10), okay?

OpenStudy (anonymous):

so u get x² + x + 10 = 30, x² + x - 20 = 0, then (x+5)(x-4) = 0, x = -5, x = 4

OpenStudy (anonymous):

and y would be root (x+10)

OpenStudy (anonymous):

so you plug that into it how??

myininaya (myininaya):

2nd equation we have y^2=10+x 1st equation we have x^2+10+x=30 x^2+x+10-30=0 x^2+x-20=0 (x+5)(x-4)=0 gives x=-5,4 y^2=10+x so y=+ or - sqrt(10+x) y=+sqrt(10+x) y=sqrt(10+-5)=sqrt(5) y=sqrt(10+4)=sqrt(14) also we have y=-sqrt(10+x) y=-sqrt(10-5)=-sqrt(5) y=-sqrt(10+4)=-sqrt(14) so we have 4 points of intersection

myininaya (myininaya):

(-5,sqrt(10)) (-5,-sqrt(10)) (4,sqrt(10)) (4,-sqrt(10))

OpenStudy (anonymous):

myininaya you seem like a very nice person, can we talk on group chat if ur dont answering this ques?

OpenStudy (anonymous):

its still saying my answer is wrong??

OpenStudy (anonymous):

nm

myininaya (myininaya):

wait my y^2 was wrong y^2=x-10 is the mistake

OpenStudy (anonymous):

so it wuld b 4roto 14 I got it thank you gor you help

myininaya (myininaya):

no wait it was right it was -10 not 10 nvm i still stand by my answers

OpenStudy (anonymous):

ok thanks got it

myininaya (myininaya):

:) ok cool

OpenStudy (anonymous):

can u help me too plz

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