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Mathematics 17 Online
OpenStudy (anonymous):

Find the point on the parabola y = x^2 -5x + 6 that's closest to the origin.

OpenStudy (anonymous):

the general co ordinate of a point on the graph is (x, x^2 -5x +6) { x,y}

OpenStudy (anonymous):

the distance of this point o the origin is sqrt( x^2 + (x^2 -5x+6)^2 )

OpenStudy (anonymous):

so d= sqrt{ x^2 +(x^2 -5x+6)^2}

OpenStudy (anonymous):

but , minimising the sqrt is the same as minimising the expression under the sqrt

OpenStudy (anonymous):

so take d=distance = x^2 +(x^2 -5x+6)^2 and minimise that function

OpenStudy (anonymous):

the minimum will occur when x= 3/2

OpenStudy (anonymous):

then sub this value back into the function to get the y ordinate

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