A company’s network has computers. All communications within the network have to be encrypted. Assuming each pair of computers needs one key for encryption, how many keys will have to be distributed by a company’s Key Distribution Center if all keys have to be different?
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if there are N computers, then \[\sum_{k=1}^{N-1} k \] keys need to be distributed
ianhardinger, did you understand the answer?
not quite
i'm trying to make sense of it by looking through my notes- in a computing class that went from calculus to statistics in one lesson...I like calculus....
suppose there are 3 computers, A,B and C. you'd need one key for A-B one key for B-C one key for A-C so, for three computers, the answer is 3 keys. suppose you have four computers A,B,C,D you need a key for A-B,A-C,A-D B-C,B-D C-D so totally 7 keys.
for N=3, \[\sum_{k=1}^{N-1}k = \sum_{k=1}^{2}k = 1+2 =3\] for N=4 \[\sum_{k=1}^{N-1}k = \sum_{k=1}^{3}k = 1+2+3 =6\]
I understand when you state it like that
sorry, I meant 6 keys in the previous post. A-B,A-C,A-D B-C B-D C-D totally 6 keys
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where do i say that
click on the goog answer button next to any reply.
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it doesn't say that anywhere...I'm having JAVA issues...
oh well. thats alright
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