Question

5(4-x)=-3(x+1)-2x

Answer 1

20 -5x = -3x -3 -2x

Answer 2

x is infinity..

Answer 3

20 -5x = -3x -3 -2x
u get the final equation simplified as
20=-3 which is not possible and hence no solution

Answer 4

dont think theirs a solution with that format 5(4-x)=-3(x+1)-2x

Answer 5

-5x + 5x = -3 -20
0 = -23 ?????

Something seems to b wron in this question....

Answer 6

wait...

Answer 7

x tending to infinity can't be a solution.

Answer 8

all though it satisfies the set of relation...u still dont write it ....

Answer 9

5(4-x)=-3(x+1)-2x
5(4/x-1)=-3(1+1/x)-2
20/x-5=-3-3/x-2
23/x=0
so x tends to infinity...

Answer 10

thanks guys

Answer 11

yes , but u won't include x->infinity int the solution set.

Answer 12

if he doesn't include x-> infinity then the question is not valid......

Answer 13

@dipankar : yea...

Answer 14

tends to infinity??
\[5(4-x)=-3(x+1)-2x\]
\[20-5x = -3x-3-2x\]
\[20 -5x=-5x-3\]
and obviously there is no solution because you have -5x on both sides and different constants. like trying to solve x = x + 1 for x. if you are foolish enough to continue you would add 5x to both sides to get
\[20=-3\] a contradiction