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would 81x^2+72x+16 be (9x+9)(9x+7) in factored form?
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no because \[7\times 9\neq16\]
so 8 and 2?
but what about the 72?
no. you got the 9 right. what is 16 the square of?
that is the one that will give it to you
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16^2 is 256
question is "what is 16 the square of" or "what number squared gives 16"
4
yes and that completes the problem (and completes the square)
(9x+4)^2
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the end part would be 63 instead of 16
So (9x+4)(9x+4) is the answer?
yes
gblover multiply out \[(9x+4)^2\] and see that it is right
9x*9x=81x^2, 9x*4*2=72x, 4*4=16
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first term will be \[81x^2\] last term will be \[4^2=16\] and middle term will be \[2\times 9\times 4x\]
what pmel11 said
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