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Mathematics 11 Online
OpenStudy (anonymous):

need help on these

OpenStudy (anonymous):

here is attachment all of them

OpenStudy (anonymous):

So basically quadratic formula should be written \[ax ^{2}+bx+c=0\] So the first one would be a=1,b=3,c=2

OpenStudy (anonymous):

looks like some factor and some do not

OpenStudy (anonymous):

\[y=-b \pm \sqrt{b^2-4ac}/(2a)\]

OpenStudy (anonymous):

first one is \[(x+1)(x+2)=0\]

OpenStudy (anonymous):

second one is \[(x-1)^2=0\]

OpenStudy (anonymous):

third and 4th do not factor over integers, so you need the formula

OpenStudy (anonymous):

The discriminate is \[b ^{2}-4ac\] If is is more than 0 there is two solutions If is equal to 0 there is one solution If it is less than 0 there are no solutions So for question 13 it is -7 so there are no solutions

OpenStudy (anonymous):

but actually now that i look at the question (always helpful) it does not ask you to solve does it?

OpenStudy (anonymous):

only says "identify a, b, c" so your job is only to write them, not to solve !

OpenStudy (anonymous):

that should be straightforward enough. the general form is \[ax^2+bx+c=0\] so only have to pick out what is a, what is b, and what is c

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