Question

Put 2x^2+3x=(3x-1)^2-x^2 into ax^2+bx+c=0

Answer 1

I have tried but I don't understand.

Answer 2

Start by expanding out the \[(3x-1)^2\] bit.

Answer 3

I think it'll be easier after that.

Answer 4

I got 9x^2-3x-3x+1

Answer 5

-3-3 is -6

Answer 6

nice dat u've tried.

2x^2+3x=9x^2+1-6x-x^2
=>2x^2-8x^2+3x+6x-1=0
therefore, -6x^2+9x-1=0

Answer 7

So the answer is 7x^2-9x+1=0?

Answer 8

\[(3x-1)^2 = 9x^2 -6x +1\]
\[\implies (3x-1)^2-x^2 = 8x^2 - 6x + 1\]

Answer 9

Then use that in your original and you should get the right thing.

Answer 10

I meant +1

Answer 11

??? I still don't get it. is it 7x^2-9x+1=0?

Answer 12

@hpslytherin ... getto see my work out, guess u'll understand.