Question

how to find domain of real-valued function ( g o h)
g(x) 4x-1 h(x) sq rt (x-4) close sq rt

Answer 1

interval notation

Answer 2

is the question h(x)=sqrt(x-4) ? or some thing more with h(x)?

Answer 3

\[(g\circ h)(x) = g(h(x)) = 4(\sqrt{x-4}) - 1\]

Answer 4

You just plug in h(x) for x in g(x)

Answer 5

i got that much but what is the domain
??

Answer 6

so here for the square root to be defined x-4>=0 and hence x>=4
therefore the domain is x>=4

Answer 7

so in interval notation (4, \[\infty\]

Answer 8

whoops lol (4, infinity]

Answer 9

?

Answer 10

\[x \in [4,\infty)\]

Answer 11

x can be 4, and any other number up to (but never including) infinity.

Answer 12

thnks