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Mathematics 16 Online
OpenStudy (anonymous):

Give the value of x where f has a removable discontinuity

OpenStudy (anonymous):

OpenStudy (anonymous):

x = 1

OpenStudy (anonymous):

no, its x = 0

OpenStudy (anonymous):

is that because the 1 has a black circle?

OpenStudy (anonymous):

yes so u can move that circle to 0 instead

OpenStudy (anonymous):

hence the name

OpenStudy (dumbcow):

yep x=0

OpenStudy (anonymous):

what abt the value of x where there is jump discontinuity? thanks!

OpenStudy (anonymous):

that would be 1

OpenStudy (anonymous):

?

OpenStudy (anonymous):

should be x = 2

OpenStudy (anonymous):

whoops I go that wrong; was looking at the vertical asymptote by mistake

OpenStudy (anonymous):

at 1 theres infinite discontinuity

OpenStudy (anonymous):

do you always take teh value w the black dot because that is an actual pt?

OpenStudy (anonymous):

thanks for your help!

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