Algebra. Solve by elimination method.
2x+3y=6
3x+5y=15

Question

Algebra. Solve by elimination method. 
2x+3y=6
3x+5y=15

owlfred · Answer

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watchmath · Answer

Multiply the first equation by -3 and the second by 2 to get
-6x-9y=-18
6x+10y=30
Add them to get
y=22
Substitute to the first equatin
2x+66=6
2x=-60
x=-30
Therefore (-30,22) is the solution.

anonymous · Answer

Isn't -18 + 30= 12?

gw2011 · Answer

3x+5y=15
2x+3y=6

Multiply the first equation by 2 and the second by 3 to find y and you get:

6x+10y=30
6x+9y=18   Subract this equation from the first one and you get:

y=12  Substitute this value into one of the equations and you get:

2x+3y=6
2x+3(12)=6
2x+36=6
2x=-30
x=-15

Therefore, x=-15 and y=12