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Mathematics 21 Online
OpenStudy (anonymous):

how do I find a vertex on the graph? claude

OpenStudy (owlfred):

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

OpenStudy (amistre64):

look for the bends in the graph; they indicate where the graph crosses its axises of symetrry

OpenStudy (amistre64):

a parabola has one vertex; an ellipse has 4; and a hyperbola has 2

OpenStudy (anonymous):

amistre thanks for your help that's great; can you tell me how to find a vertex formula?

OpenStudy (anonymous):

For what type of conic? There's no cut and dry formula for all of them.

OpenStudy (anonymous):

hello guys, can this answer be symplify? \[2/2\sqrt{2x+1}\]

OpenStudy (amistre64):

\(\frac{2}{2\sqrt{2x+1}}\) can be simplified by reducing the 2/2 to 1/1; and depending on how the material likes it, you might wanna rationalize the denominator

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