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can anyone help me solve this: f(x)= 1/3x^2-2x f(x+h)=?
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just replace 'x' with 'x+h'
1/3x^2 -2x 1/3(x+h)^2 -2(x+h)
f(x+h)=1/3*(x+h)^2-2(x+h)
how the equation looks I cant tell cause of the way its presented
\[f(x)=\frac{1}{3x^2 -2x}\] \[f(x+h)=\frac{1}{3(x+h)^2 -2(x+h)}\]
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amistre, how do u get those horizontal lines for division symbol ?
magic!
i think about it real hard like lol
\[\frac{top}{bottom}\_] ^ remove the '_'
And \({this \over that}\_) works for simple stuff
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We can see that \(this\over that\) is for inline typing and \[\frac{top}{bottom}\] breaks the line
how to evaluate this limit g(x)= √2x+1 lim (g(x+h)-g(x))/h h---0
what is √2x+1
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