what must you add to make it a complete square? x^2+8x=11?
you got this yes? half of 8 is 4, 4 squared is 16 done
+5
16
add 16 on both sides to make it a perfect square on the left hand side. (x+4)^2=27
I just don't understand how to get these answers.... I wasn't taught this...
to get a perfect square see the single degree x term and see if u can seperate into equal half if so den multiply those term u will get a answer and den see wat number u can add to get that value hope ull get it
yah you just need to know the formula (a+b)^2=a^2+2ab+b^2 you should get your equation in the form of a^2+2ab+b^2 from the question x^2+8x=11 x^2+8x-11=0 simplify like this x^2+(2)(4)(x)-11=0 from that a=x and b=4 so -11 should be replaced by b^2 to make it perfect square so to get b^2=16 add 27 . then it becomes x^2+8x+16=0
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