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Mathematics 12 Online
OpenStudy (anonymous):

Evaluate the limit as x goes to 2

OpenStudy (anonymous):

OpenStudy (anonymous):

factor and cancel yes?

OpenStudy (anonymous):

60

OpenStudy (anonymous):

I got 60 too

OpenStudy (anonymous):

\[5x^3-40=5(x^3-8)=5(x-2)(x^2+2x+4)\]

OpenStudy (anonymous):

it is gonna be 0/0 you can use L'hospital rule and it goes out easily

OpenStudy (anonymous):

not at l'hopital yet. just factor, cancel, plug in 2

OpenStudy (anonymous):

cool did this one right!

OpenStudy (anonymous):

you get \[\frac{5x^2-40}{x-2}=5(x^2+2x+4)\] plug in 2 get out 60 good work !

OpenStudy (anonymous):

oh ok sorry

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