Mathematics
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OpenStudy (anonymous):
Evaluate:
lim x^2-x+6/ x-2
x->2
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OpenStudy (anonymous):
8/0 = infinity
OpenStudy (anonymous):
The answer is 5, that's what it says in the book. I don't know how they get that.
OpenStudy (anonymous):
s its infinite
OpenStudy (anonymous):
the book is wrong
OpenStudy (anonymous):
just substitute x=2 in all places of x
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OpenStudy (anonymous):
I did that and get 0/0
OpenStudy (anonymous):
So it's infinite?
OpenStudy (anonymous):
4-2+6 = 8
OpenStudy (amistre64):
factor the top to see if it cancels the bottom
OpenStudy (anonymous):
Oh.. sorry. It was suppose to be x^2 +
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OpenStudy (amistre64):
x^2-x+6 (x+3)(x-2)
-------- = ----------
x-2 (x-2)
OpenStudy (amistre64):
as x goes to 2; (x+3) goes to 5
OpenStudy (amistre64):
...... lol, im making up my own problems i think
OpenStudy (anonymous):
x^2-x+6 = (x+3)(x-2) it is not right
OpenStudy (anonymous):
There we go. Thanks Amsitre :)
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OpenStudy (anonymous):
Amistre is right.
OpenStudy (amistre64):
there we ALMOST go ;)
OpenStudy (anonymous):
I forgot to factor.
OpenStudy (amistre64):
did you typo the question?
OpenStudy (anonymous):
Yeah
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OpenStudy (anonymous):
(x+3)(x-2) = x^2 -x -6
OpenStudy (amistre64):
hah! .... I was right :)
OpenStudy (amistre64):
and that equals x^2 +x-6
OpenStudy (anonymous):
right sorry
OpenStudy (amistre64):
typing and computing are two seperate brain activities ;)
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OpenStudy (anonymous):
lol