OpenStudy (anonymous):

hELP

6 years ago
OpenStudy (anonymous):

what do you need help on?

6 years ago
OpenStudy (anonymous):

whats your q?

6 years ago
OpenStudy (anonymous):

4X^2(3X^2)(X)=

6 years ago
OpenStudy (anonymous):

you can use:\[x ^{a}\times x ^{b} = x^{a+b}\]

6 years ago
OpenStudy (anonymous):

you can break this down into \[4\times x ^{2}\times 3\times x^{2} \times x^1\]

6 years ago
OpenStudy (anonymous):

i dont get this???

6 years ago
OpenStudy (anonymous):

you can do the 4x3 easily and then use the equation the combine the x together

6 years ago
OpenStudy (anonymous):

so you get 12 and then the exponents are 2, 2, 1

6 years ago
OpenStudy (anonymous):

so think of 2, 2, 1 as a, b, c

6 years ago
OpenStudy (anonymous):

Then \[x^{2}\times x^{2} \times x^{1} \] which is \[x^{a}\times x^{b} \times x^{c} = x^{2+2+1}\]

6 years ago
OpenStudy (anonymous):

combine the 12 you got from 4 and 3 you get \[12\times x^{5} \] which is your answer

6 years ago