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The height of a football "t" seconds after a punt depends upon the intial height and velocity of the ball, and that on the downward pull of gravity. Supposed a punt leaves the kicker's foot at an initial height of .75 meters and with an initial velocity of 32 meters per second. what is a rule relating h(t) in meters and time t in seconds that the ball was in the air for this punt,.
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I will assume that initial velocity of 32 m/s is all in the vertical direction then, the rule is: h(t)=initial height+initial velocity*time+1/2 acceleration*time^2 acceleration due to gravity is 9.8 m/s^2 so \[h(t)=.75+32t+1/2*9.8*t^2\]
thank you very much
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