In Equation such as 6x-y=29 and then i have x=y-9 i sub in y-9 6(y-9)-y=-29 solve for y which then equals 6y-54-y=-29 5y=25 ( how does it get their from 6y-54-y=-29?)
how can you get 5y=25 from that and why. i need to find the value of y but i dont understand after the point of 6y-54-y=-29 that you then get 5y=25
is it 29 or -29 in the 1st eq?
-29
Well you have 6y - 54 - y on the left side. And you can rewrite that by the commutative property to be 6y -y - 54 Then you can combine the first two terms 6y-y = 5y so you get 5y - 54 and that equals -29
With me so far?
yes so i would subtract 1y to each side?
No, you add 54 to both sides.
like 6y- 1y = 5y-54
Wait what?
I think you missed something
You have this: \[\text{ ( given ) }6y - 54 - y = -29\]\[\text{(commute)}\implies 6y - y-54 = -29\]\[\text{(combine first two terms)}\implies 5y - 54 = -29\]
ohhh i get it
Because 6 y's minus 1 y is 5 y's. Just like 6 oranges minus 1 orange is 5 oranges.
okay. so anything other equation like that i should combine like terms
yeah
thank you
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