In Equation such as 6x-y=29
and then i have x=y-9 i sub in y-9
6(y-9)-y=-29
solve for y which then equals
6y-54-y=-29
5y=25 ( how does it get their from 6y-54-y=-29?)
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OpenStudy (anonymous):
how can you get 5y=25 from that and why. i need to find the value of y but i dont understand after the point of 6y-54-y=-29 that you then get 5y=25
OpenStudy (anonymous):
is it 29 or -29 in the 1st eq?
OpenStudy (anonymous):
-29
OpenStudy (anonymous):
Well you have
6y - 54 - y
on the left side. And you can rewrite that by the commutative property to be
6y -y - 54
Then you can combine the first two terms 6y-y = 5y so you get
5y - 54 and that equals -29
OpenStudy (anonymous):
With me so far?
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OpenStudy (anonymous):
yes so i would subtract 1y to each side?
OpenStudy (anonymous):
No, you add 54 to both sides.
OpenStudy (anonymous):
like 6y- 1y = 5y-54
OpenStudy (anonymous):
Wait what?
OpenStudy (anonymous):
I think you missed something
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OpenStudy (anonymous):
You have this:
\[\text{ ( given ) }6y - 54 - y = -29\]\[\text{(commute)}\implies 6y - y-54 = -29\]\[\text{(combine first two terms)}\implies 5y - 54 = -29\]
OpenStudy (anonymous):
ohhh
i get it
OpenStudy (anonymous):
Because 6 y's minus 1 y is 5 y's. Just like 6 oranges minus 1 orange is 5 oranges.
OpenStudy (anonymous):
okay. so anything other equation like that i should combine like terms
OpenStudy (anonymous):
yeah
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