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sequence..(1+1/2n)^n..converge or diverge?? work.. ln An = n * ln(1+1/2n) lim of n = infinity lim of ln(1+1/2n) = 0 soo can i say the limit of ln An is infinity*0 = 0..???
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no
you must take the the n in the denominator , and apply la hopitals rules
because its an indeterminate form , infinity times zero
and remember that the answer you get for the limit will not be the final answer , it will be e^A , where A is whatever the limit is
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