Question

I forgot how to solve logs
how do i solve loga 64=3

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

a^3 = 64
a = 4

Answer 3

loga(a)=1

loga(b)^n=nloga(b)

use both of them u'll end up getting the him's answer :)

Answer 4

logs point to exponents:

loga(64) = 3 points the base 'a' at the exponent '3' and lets us know it equals '64'

Answer 5

loga(64) = 3

64 = a^3

a = cbrt(64)

Answer 6

what about log5 (x2+7x)=log5 30....do i set them equal because the bases are the same?

Answer 7

yes

Answer 8

all things being the same; the differences equate

Answer 9

and recall that logs only work on values greater than 0; log(-12) is undefined

Answer 10

thanks i'll remember that my final is is like 15 minutes