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limit as x goes to 0: (cos(4x)-1)/5x
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I pulled out a -1 for the numerator
This one is tricky because again if you put in x goes to 0 you get 0/0 I would recommend using L'hopital's rule, if you are willing to give it a shot
use l'Hôpital's rule ... differentiate
=lim (-4sin4x)/5 = 0
we haven't been taught that yet _ sorry guys and thanks for the patience ! using pinching theorem at the moment
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Yeah, you need to use l'Hopital's rule to see which one is approaching 0 faster.
can you not pull out -1(1+cos(4x) and solve from there?
If you pull out a -1 you would have -1(1 - cos(4x))
Which has the same trouble.
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check out my attachment it is with l'hospital's rule
without*
you don't need l'hospital eventhough he is a great guy
thank you so much!
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