Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

limit as x goes to 0: (cos(4x)-1)/5x

OpenStudy (anonymous):

I pulled out a -1 for the numerator

OpenStudy (anonymous):

This one is tricky because again if you put in x goes to 0 you get 0/0 I would recommend using L'hopital's rule, if you are willing to give it a shot

OpenStudy (anonymous):

use l'Hôpital's rule ... differentiate

OpenStudy (anonymous):

=lim (-4sin4x)/5 = 0

OpenStudy (anonymous):

we haven't been taught that yet _ sorry guys and thanks for the patience ! using pinching theorem at the moment

OpenStudy (anonymous):

Yeah, you need to use l'Hopital's rule to see which one is approaching 0 faster.

OpenStudy (anonymous):

can you not pull out -1(1+cos(4x) and solve from there?

OpenStudy (anonymous):

If you pull out a -1 you would have -1(1 - cos(4x))

OpenStudy (anonymous):

Which has the same trouble.

myininaya (myininaya):

myininaya (myininaya):

check out my attachment it is with l'hospital's rule

myininaya (myininaya):

without*

myininaya (myininaya):

you don't need l'hospital eventhough he is a great guy

OpenStudy (anonymous):

thank you so much!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!