solve system by anymeathod
4x-7y=-13
3x-5y=-9

Question

owlfred · Answer

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anonymous · Answer

thank you :)

anonymous · Answer

Multiply both equations by 3 and -4,
so you get
$$12x-21y=-39$$
and 
$$-12x+20y=36$$

add to get
$$-y=-3$$
or
$$y=3$$

substitute and you get
$$x=2$$

anonymous · Answer

long problem :/ especially to do online lol.

So I, personally, would use substitution for this type of problem.

4x-7y=-13
3x-5y=-9

Second equation: y=3/5x+9/5

Substitute second equation to first equation.

4x-7(3/5x+9/5)=-13
4x-21/5x-63/5=-13
-1/5x=-2/5
x=2.

substitute 2 for x into the second equation.

3(2)-5y=-9
6-5y=-9
-5y=-9/6
y=9/30
y=3/10.

That should be right.