Question

the length of a rectangle is more than twice its width, and the area of the rectangle is . Find the dimensions of the rectangle.

Answer 1

what is the area?

Answer 2

he length of a rectangle is 1ft more than twice its width, and the area of the rectangle is 66ft^2 . Find the dimensions of the rectangle.

Answer 3

okay this is pretty simple.
suppose the width is W feet.
what can you say about the length?

Answer 4

ok, so the width would be x, while the length would be 2x+1

so the equation would be 2x^2+x=66

You would factor it to 2x^2+x-66=0
So it would be: (2x-11)(x+6)=0.

x=-6,11/2

Since -6 is negative, 11/2 is the width.

The length would be 12, since 2(11/2)+1=12.

Dimensions= 12 by 11/2.

Answer 5

what some1 said.

Answer 6

:)