Question

what is the LCD of x over 2x+2 = -2x over 4x+4 plus 2x-3 over x+1

Answer 1

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Answer 2

\[\frac{x}{2x+2} = \frac{-2x}{4x+4} + \frac{2x-3}{x+1}\]
Factor the all the denominators first.
\[\frac{x}{2(x+1)} = \frac{-2x}{4(x+1)} + \frac{2x-3}{x+1}\]
You may want to simplify that second fraction.
\[\frac{x}{2(x+1)} = \frac{-x}{2(x+1)} + \frac{2x-3}{x+1}\]
Notice that all the fractions have the factor (x+1), and that two of the fractions have 2 as a factor as well. So the LCD = 2(x+1).

Answer 3

Thank you so much!! Thats so simple and I was making much harder than it was! you are awesome!!!