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Simplify expression. Assume that all variables represent positive real numbers. (x^2y^6) 1/2 over (-2xy)^3
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I agree but I still need to solve it.
Here:\[{(x^2y^6)^{1/2} \over (-2xy)^3}={xy^3 \over -8x^3y^3}=-{1 \over 8x}.\]
how did you get xy^3 over -8x^3y^3
Distribute the exponent over all of them as \((x^2)^{1/2}\) for example, which is equal to \(x\).
what happen to the -8x^3? Why is it just -1/8x?
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