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simplify the following expression: 8√8x^12
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x^12 under root becomes x^6. So the equation would be [x^6*8*\sqrt{8}\]
You can also bring a 2 out of the square root because 2 * 4 = 8. Square root of 4 is 2.
\[8\sqrt{8x^{12}}=8(\sqrt8)x^6=16\sqrt2 x^6\]. Since \(\sqrt{8}=2\sqrt{2}\).
How did the 12 go to 6? Also where do I click to say that this questions has a good answer?
Nevermind, found it! But how did the 12 go to 6?
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the x^12 = x^6 times x ^6 or (x^6)^2. so when x^12 is taken under sqrt, it becomes x^6
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