Question

SETTING UP PROBLEM
Two planes make a 1500 mile flight, one flying 50 miles per hour faster than the other. The quicker plane makes the trip 1 hour faster. How long did it take the slower plane to complete the flight

Answer 1

someone help

Answer 2

jus trying

Answer 3

ok

Answer 4

let slower plane speed =x

then faster plane speed=x+50

distance=1500

time=distance/velocity

so

time taken for slower plane=1500/x

time taken for slower plane=1500/x+50

difference between them is 1hr

1500/x+50 -1500/x==1

solve for x

and fnd the time using 1500/x+50

Answer 5

speed = distanve * time
let speed of first plane be v, d = 1500, t = time taken
speed of the second plane is 50 faster (v+50) and time taken is 1 slower = d-1
First plane:
v = 1500 / t
Second plane:
v + 50 = 1500 / (t - 1)

solving these two equations will give you the answer

Answer 6

its 6 hrs

Answer 7

THANKS EVERYONE!

Answer 8

let the slower plane took t hours.
so faster plane took (t-1)hours
speed of slower plane=(1500/t) miles/hr
speed of faster plane={1500/(t-1)} miles/hr
acc. to ques.,

{1500/(t-1)}=(1500/t)+50
solve for t which is ur answer.

Answer 9

t=1500/v
v+50=1500/(t-1)

solve t