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Find the exact value sin^1 0
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\[\sin^{-1}(0)=0\]
thats it
Yeah, its 0. Because you want "the angle that makes sin(x) zero. Which is zero.
thank u
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wat bout this one
You want the "angle that makes sin sqrt(2)/2". You know that sin(pi/4)=sqrt(2)/2. so the ARCSIN(sqrt(2)/2) is pi/4.
pi/4 You should really memorize the values of the special trig functions -- they pop up everywhere and you can derive others from them quite easily when you're taking a test http://www.analyzemath.com/trigonometry/special_angles.html
thank u guys
wat abut cos
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